x-6=x^2-5x+3

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Solution for x-6=x^2-5x+3 equation: 



x-6=x^2-5x+3

We move all terms to the left:

x-6-(x^2-5x+3)=0

We get rid of parentheses

-x^2+x+5x-3-6=0

We add all the numbers together, and all the variables

-1x^2+6x-9=0

a = -1; b = 6; c = -9;
Δ = b2-4ac
Δ = 62-4·(-1)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{-2}=+3$

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